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Dilute nitric acid on electrolysis using platinum electrodes yields.

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Both oxygen & hydrogen at cathode

Oxygen at cathode and H₂ at anode

H₂at cathode and O₂at anode

Both oxygen & hydrogen at anode

answer is C.

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Detailed Solution

Cathode reaction :

$2 H_{2} O + 4 e^{-} \to H_{2} + 2 {OH}^{-}$

Anode reaction :

$2 H_{2} O - 4 e^{-} \to O_{2} + 4 H^{+}$

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