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Dimensional formula of electric flux is

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${ML}^{3} T^{- 3} I^{- 1}$

${ML}^{2} T^{- 1} I^{- 1}$

$M^{2} {LT}^{- 3} I^{- 1}$

$M^{- 2} {LT}^{- 1} I^{- 2}$

answer is A.

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Detailed Solution

$Q = ε_{0} . ϕ_{E}$

$∴ [ϕ_{E}] = \frac{[Q]}{[ε_{0}]} = [Q] . [\frac{F . r^{2}}{Q^{2}}] = [\frac{F . r^{2}}{Q}]$

$= [\frac{{MLT}^{- 2} \times L^{2}}{IT}] = [{ML}^{3} T^{- 3} I^{- 1}]$

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