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Q.

Dimensions of $\frac{1}{μ_{0} \in_{0}},$ where symbols have their usual meaning are

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a

$L^{- 1} T$

b

$L^{2} T^{- 2}$

c

$L^{2} T^{2}$

d

$L T^{- 1}$

answer is C.

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Detailed Solution

$C = \frac{1}{\sqrt{μ_{0} \in_{0}}} \Rightarrow C^{2} = \frac{1}{μ_{0} \in_{0}} So, Dimensional formula is L^{2} T^{- 2}$

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