Diploid plant cell (2n = 8) undergoes meiotic cell cycle. How many possible bivalents can be observed during the process?

Since, 2n = 8 (for a diploid plant cells)
Number of bivalents $=\frac{\text{ Total number of chromosome }}{2}$
                                 $=\frac{8}{2}=4 \mathrm{Bivalents}$