Dipole moment of HX is 1D. If the H-X bond length 1.25A0. Percentage of Ionic character in HX is

μcalculate=e×d μcalculate=4.8×10−10×1.25×10−8 μcalculate=6×10−18esu.cm=6D ∴%I.C.=μobsμcal×100=1D6D×100=16.6

Dipole moment of HX is 1D. If the H-X bond length 1.25A0. Percentage of Ionic character in HX is

μcalculate=e×d μcalculate=4.8×10−10×1.25×10−8 μcalculate=6×10−18esu.cm=6D ∴%I.C.=μobsμcal×100=1D6D×100=16.6

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Dipole moment of HX is 1D. If the H-X bond length 1.25A⁰. Percentage of Ionic character in HX is

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33.3

16.6

answer is B.

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Detailed Solution

$μ_{c a l c u l a t e} = e \times d$
$\begin{aligned} μ_{calculate} = 4.8 \times 10^{- 10} \times 1.25 \times 10^{- 8} \\ μ_{calculate} = 6 \times 10^{- 18} esu.cm = 6 D \\ ∴ % I.C. = \frac{μ_{obs}}{μ_{cal}} \times 100 = \frac{1 D}{6 D} \times 100 = 16.6 \end{aligned}$