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Q.

Displacement current through a capacitor of capacitance 2 µF is 4mA. The rate of potential difference across that capacitor is N × 10³ V/s. What is the value of ‘N’.

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answer is 2.

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Detailed Solution

$I_{d} = C [\frac{dv}{dt}]$

$\frac{dV}{dt} = \frac{i_{d}}{C} = \frac{4 \times 10^{- 3}}{2 \times 10^{- 6}} = 2 \times 10^{3} volt / s$

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Displacement current through a capacitor of capacitance 2 µF is 4mA. The rate of potential difference across that capacitor is N × 103 V/s. What is the value of ‘N’.