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Q.

Displacement of body is (5i+3j4k)m when a force (6i+6j+4k)N acts for 5 sec. The power in watt is

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a

3.2

b

16

c

6.4 

d

9.6 

answer is C.

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Detailed Solution

s=(5i^+3j^4k^)m

t=(6i^+6j^+4k^)Nt=5  sec

Power P=F.St=(5i^+3j^4k^).(6i^+6j^+4k^)5=30+18165=325=6.4  W

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