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Q.

Displacement time graph of particle moving in a straight line is as shown in figure.

From the graph we can conclude that work done on the block is :

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a

negative from t3 to t4.

b

positive from 0 to t1 

c

zero from t2 to t3 

d

negative from t1 to t2

answer is A, B, C.

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Detailed Solution

Slope of the graph at a point = velocity,t1=0 to t1 velocity increases.

t1 to t2 velocity decreases, t2 to t3  velocity zero and t3 to t4 velocity is constant.

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Displacement time graph of particle moving in a straight line is as shown in figure.From the graph we can conclude that work done on the block is :