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Q.

Dissolution of an ionic solid XY in water is endothermic to an extent of 4 kJ per mol. If lattice enthalpy of XY(s) is + 788 kJ per mol, then hydration enthalpy of Y− would be (the ratio of hydration enthalpy of X : Y is 5 : 4)

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a

– 435.55 kJ

b

– 394 kJ

c

– 348.45 kJ

d

– 549.9 kJ

answer is C.

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Detailed Solution

ΔHSolution=ΔHlattice+ΔHHyd

+4kJ=+788+ΔHHyd

ΔHHyd=−784 kJ

Hydration enthalpy of

Y−=49×(784)=−348.45 kJ

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