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Q.

Dissolving 120g of urea (mol. wt. 60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is

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a

2.05 M

b

2.00 M

c

1.78 M

d

2.22 M

answer is C.

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Detailed Solution

Toatl mass of solution
= 1000 + 120 = 1120
$v o l u m e = \frac{m a s s}{d e n s i t y} = \frac{1120}{1.15} m l$
Molarity = $\frac{n_{s o l u t e}}{V (m l)} \times 1000$

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