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Q.

Distance between centers of two spheres A and B, each of radius R as shown in figure. Sphere B has a spherical cavity of radius R/2 such that distance of centre of cavity is (r – R/2)  from the centre of sphere A and R/2 from the centre of sphere B. Di-electric constant of material of each sphere is K = 1 and material of each sphere has a uniform charge density ρ  per unit volume. The interaction potential energy of the two spheres is found to be  πρ2R6(7r4R)Kε0r(2rR). The value of K is
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a

11

b

7

c

5

d

9

answer is D.

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Detailed Solution

U=Kq1q2r

U0=U12+U13

U12=K(43πR3ρ)(43πR3ρ)r

=4πρ2R69ε0r

U13=K(43πR3ρ)[43π.(R2)3(ρ)](rR2)=πρ2R69ε0(2rR)

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