Distance between two parallel planes 2x+y+2z=8 and 4x+2y+4z+5=0 is

Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

Distance between two parallel planes $2 x + y + 2 z = 8$ and $4 x + 2 y + 4 z + 5 = 0$ is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$\frac{3}{2}$

$\frac{9}{2}$

$\frac{5}{2}$

$\frac{7}{2}$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The planes are $2 x + y + 2 z = 8 \to 1$

And $4 x + 2 y + 4 z + 5 = 0$ or $2 x + y + 2 z + \frac{5}{2} = 0 \to 2$

$∴$ Distance between (1) and (2) $= | \frac{\frac{5}{2} + 8}{\sqrt{2^{2} + 1^{2} + 2^{2}}} | = | \frac{21}{2 \sqrt{9}} | = \frac{7}{2}$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE