Divide Rs. 3600 into two parts such that if one part is lent at 9 % per annum and the other at 10 % per annum, the total annual income is Rs. 333.

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1st part = Rs. 2700 & 2nd part = Rs. 900

1st part = Rs. 2600 & 2nd part = Rs. 1000

1st part = Rs. 2500 & 2nd part = Rs. 1100

1st part = Rs. 2400 & 2nd part = Rs. 1200

answer is A.

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Detailed Solution

Given the total annual income is Rs. 333.
We know that,
S.I.

= P × R × T 100

.
Let the first part = x.
Therefore, the second part = 3600 – x.
Now the S.I. on x at 9 % is,

S . I = x × 9 × 1 100 S . I = 9 x 100

Now, S.I. on (3600 - x) at 10 % is,

S . I = 3600 − x × 10 × 1 100 S . I = 3600 − x 10

According to the question,

9 x 100 + 3600 − x 10 = 333 − x + 36000 100 = 333 x = 36000 − 33300 x = 2700

1st part = Rs. 2700
2nd part is,
= 3600 – 2700
= Rs. 900
Therefore, the 1st part is Rs. 2700 and the 2nd part is Rs. 900.
Hence, option 1 is correct.

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