Dividing 4500 into two parts such that 5% of the first part is equal to 10% of the second part, the two parts are [[1]] and [[2]] respectively.

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Dividing 4500 into two parts such that 5% of the first part is equal to 10% of the second part, the two parts are 3000 and 1500 respectively.
It is given that the number 4500 is to be divided into two parts, with the condition that 5% of the first part should be equal to 10% of the second part.
Now, assume the first part of the number is x.
Now, as 4500 is divided into two parts, so the second part must be (4500-x).
Next, according to the given condition, 5% of the first part is equal to 10% of the second part.
This can be expressed mathematically as follows,
5% of x = 10% of

(4500 − x)

5100 × x = 10100 × (4500 − x)

It can be observed that 100 is appearing on both sides of the equation.
So, canceling them out, the equation can be written as follows,

5 x = 10 (4500 − x)

Simplifying,

5 x = (10 × 4500) − (10 × x)

5 x = 45000 − 10 x

Adding

10 x

on both sides, we get,

5 x + 10 x = 45000 − 10 x + 10 x

15 x = 45000

Finally, divide each side by 15 to get the value of the variable x as follows,

15 x 15 = 4500015

x = 3000

So, we get the first part of the number as 3000. Now, to get the value of the second part, substitute 3000 for x in the term (4500-x) as assumed, i.e.

4500 − 3000 = 1500

So, the second part is 1500.
Hence, 3000 and 1500 are first and second parts of 4500 which satisfy the given condition, i.e., 5% of the first part is equal to 10% of the second part.

Dividing 4500 into two parts such that 5% of the first part is equal to 10% of the second part, the two parts are [[1]] and [[2]] respectively.

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