Dividing 4500 into two parts such that 5% of the first part is equal to 10% of the second part, the two parts are [[1]] and [[2]] respectively.

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Dividing 4500 into two parts such that 5% of the first part is equal to 10% of the second part, the two parts are 3000 and 1500 respectively.It is given that the number 4500 is to be divided into two parts, with the condition that 5% of the first part should be equal to 10% of the second part. Now, assume the first part of the number is x. Now, as 4500 is divided into two parts, so the second part must be (4500-x).Next, according to the given condition, 5% of the first part is equal to 10% of the second part. This can be expressed mathematically as follows, 5% of x = 10% of

(4500−x)

5
    
     100
   
   ×x=
    
     10
    
     100
   
   ×(4500−x)
 It can be observed that 100 is appearing on both sides of the equation. So, canceling them out, the equation can be written as follows,

5x=10(4500−x)
 Simplifying,

5x=(10×4500)−(10×x)

5x=45000−10x
 Adding

10x
  on both sides, we get,

5x+10x=45000−10x+10x

15x=45000
 Finally, divide each side by 15 to get the value of the variable x as follows,

15x
    
     15
   
   =
    
     45000
    
     15

x=3000
   So, we get the first part of the number as 3000. Now, to get the value of the second part, substitute 3000 for x in the term (4500-x) as assumed, i.e.

4500−3000=1500
 So, the second part is 1500.Hence, 3000 and 1500 are first and second parts of 4500 which satisfy the given condition, i.e., 5% of the first part is equal to 10% of the second part.

Dividing 4500 into two parts such that 5% of the first part is equal to 10% of the second part, the two parts are [[1]] and [[2]] respectively.

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