Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of $\overline{OA}$ and $\overline{OB}$. Let them meet at P. Is PA = PB ?

Step I: Draw an angle XOY with vertex O.
Step II: Mark any point A on OY and B on OX, such that OA = OB.

Step III: Take O and A as centres and with a radius more than half of OA, draw arcs on both sides of OA. Join the intersecting points to construct the perpendicular.

Step IV: Take O and B as centres and with a radius more than half of OB, draw arcs on both sides of OB. Join the intersecting points to construct the perpendicular.
Step V: Measure the lengths of $\overline{PA}$ and $\overline{PB}$. Yes, $\overline{PA} = \overline{PB}$.