Draw the electron dot structure for, (A) Ethanoic acid (B) Hydrogen sulphide (C) Propanone (D) dichlorine.

(A) Ethanoic acid (CH₃COOH)

• Ethanoic acid has 2 parts: CH₃– and –COOH (carboxyl group).
• Oxygen atoms form double and single bonds with carbon and also have lone pairs.

Electron dot structure:

   H   H   H
   |   |   |
H–C – C – O – H
      || 
      O

(O atoms have lone pairs, but in exam diagrams you show 2 dots per lone pair around O.)

(B) Hydrogen sulphide (H₂S)

• Sulphur (S) has 6 valence electrons, forms 2 single bonds with H.
• Leaves 2 lone pairs on S.

Electron dot structure:

   H : S : H
     ..

(C) Propanone (CH₃–CO–CH₃)

• Propanone is a ketone. Central carbonyl group (C=O).
• Each O atom has 2 lone pairs.

Electron dot structure:

   H   H     
   |   |         
H–C – C – C – H
      ||
      O

(O has 2 lone pairs shown as dots.)

(D) Dichlorine (Cl₂)

• Each chlorine has 7 valence electrons.
• They share 1 electron pair to form a single bond, leaving 3 lone pairs each.

Electron dot structure:

:Cl – Cl: