During a cloudburst and lightning, light reaches 3 s earlier than sound. If the velocity of light is 3 x 10⁸ m/s and that of sound is 350 m/s. Find the distance of the cloud burst from the surface of the earth.

Let, t_l represent the time of light reaching the earth's surface.
t_s represents the time of sound reaching the earth's surface. 
v_l represents the velocity of light.
v_s represent the velocity of sound.
s represents the distance of cloudburst from the earth's surface.
Then we can write,
${\mathrm{t}}_{\mathrm{l}}=\frac{\mathrm{s}}{{\mathrm{v}}_{\mathrm{l}}},\mathrm{ }{\mathrm{t}}_{\mathrm{s}}=\frac{\mathrm{s}}{{\mathrm{v}}_{\mathrm{s}}}$
According to the given problem,
${\mathrm{t}}_{\mathrm{l}}-{\mathrm{t}}_{\mathrm{s}}=3$
$\Rightarrow \frac{\mathrm{s}}{{\mathrm{v}}_{\mathrm{l}}}-\frac{\mathrm{s}}{{\mathrm{v}}_{\mathrm{s}}}=3$
$\Rightarrow \mathrm{s}=3(3\times {10}^8-350)$ = 3(29,99,99,650) = 899998950m
During a cloudburst and lightning, Light reaches 3s earlier than sound. If the velocity of light is $3\times {10}^8 \mathrm{m}/\mathrm{s}$ and that of sound is $350 \mathrm{m}/\mathrm{s}$. Then the distance of the cloud burst from the earth is 89,99,98,950m.