During a cloudburst and the lightning, Light reaches 3 s earlier than sound. If velocity of light is 3×108 m/s and that of sound is 350 m/s. Then the distance of the cloud burst from the earth is [[1]] m.

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During a cloudburst and the lightning, Light reaches $3 s$ earlier than sound. If velocity of light is $3 \times 10^{8} m / s$ and that of sound is $350 m / s$ . Then the distance of the cloud burst from the earth is [[1]] $m$ .

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Detailed Solution

During a cloudburst and the lightning, Light reaches

3 s

earlier than sound. If velocity of light is

3 \times 10^{8} m / s

and that of sound is

350 m / s

. Then the distance of the cloud burst from the earth is

99999883.33 m

.
Let,

t_{l}

represents the time of light reaching the earth surface.

t_{s}

represents the tie of sound reaching the earth surface.

v_{l}

represents velocity of light.

v_{s}

represents velocity of sound.

s

represents the distance of cloudburst form the earth's surface.
Then we can write

t_{l} = \frac{v_{l}}{s}, t_{s} = \frac{v_{s}}{s}

By the given problem,

t_{l} - t_{s} = 3

\Rightarrow \frac{v_{l}}{s} - \frac{v_{s}}{s} = 3

\Rightarrow 3 s = 3 \times 10^{8} - 350

= 299999650

\Rightarrow s = 99999883.33 m

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