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Q.

During an adiabatic compression of 5 moles of a gas, 250 J of work was done. The change in the internal energy will be 

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a

50 J

b

-150 J

c

250 J

d

-250J

answer is C.

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Detailed Solution

In an adiabatic process, dQ=0. Therefore, dU=dW, i.e. change in internal energy = work done. Since work is done on the gas dW is negative. Hence dU=(250)=250J. Thus the internal energy increases by 250 J. Hence the correct choice is (3). 

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