During chlorination of methane to methyl chloride, the propagation step is represented by

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$\dot{C} l + \dot{C} l \to C l - C l$

${\dot{CH}}_{3} + \dot{C} l \to {CH}_{3} Cl$

${CH}_{4} + C l^{.} \to {\dot{CH}}_{3} + HCl$

$Cl - C l \overset{hv}{\to C} l^{.} + C l^{.}$

answer is C.

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Detailed Solution

During chlorination of methane to methyl chloride, the propagation step is represented by
$text CH end text subscript 4 plus C l to the power of bold. rightwards arrow stack text CH end text with dot on top subscript 3 plus text HCl end text$

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