Q.

During illness an 80 kg man ran a fever of 102.2°F instead of normal body temperature of 98.6°F. Assuming that human body is mostly water, how much heat is required to raise his temperature by that amount

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a

100 kcal

b

160 kcal

c

50 kcal

d

92 kcal

answer is B.

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Detailed Solution

Since 102.2°F →  39°C and 98.6°F → 37°C
Hence 

 

Q= m. s.

Q = 80 × 1000 × (39 – 37)
= 16 × 104cal = 160 kcal.

 

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