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During normal quiet breathing, the amount of air present in the lungs of a healthy man at the end of inspiration is about

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500 mL

1700 mL

5200 mL

2700 mL

answer is D.

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Detailed Solution

RV+ERV+TV = 1100 to 1200 + 1000 to 1100 + 500 = 2600 to 2800 mL

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