During photosynthesis 1.344 lits of dry  O₂ gas is liberated at STP. Identify correct statement from the following?

photosynthesis reaction is 

6CO₂ + 6H₂O $\underset{\mathrm{chlorophyll}}{\overset{\mathrm{h\vartheta }}{\to }}$C₆H₁₂O₆ + 6O₂

number of moles of O₂ liberated = $\frac{1.344}{22.4}$=0.06

0.01 moles of CO₂ is consumed

0.01 moles of water is consumed

0.01 mole of glucose is formed =0.01 x 180 =1.8 gm