During the charging of lead storage battery, the reaction at anode is represented by

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$P b^{2 +} + 2 e^{-} \to P b$

$P b^{2 +} + S O_{4}^{2 -} \to P b S O_{4}$

$P b S O_{4} + 2 H_{2} O \to P b O_{2} + S O_{4}^{2 -} + 4 H^{+} + 2 e^{-}$

$P b \to P b^{2 +} + 2 e^{-}$

answer is B.

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Detailed Solution

During charging, the lead storage battery behaves like an electrolytic cell. So, at anode the reaction is
$P b S O_{4} + 2 H_{2} O \to P b O_{2} + 4 H^{+} + S O_{4}^{2 -} + 2 e^{-}$

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