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Q.

During the discharge of a lead storage battery the density of sulphuric acid fell from 1.294 to 1.139 g.ml-1. H2SO4 of density 1.294 g.ml -1 is 39% and that of density 1.139 g.ml -1  is 20% by weight. The battery holds 3.5 L of acid and the volume practically remains constant during discharge. Calculate the number of ampere hours for which the battery must have been used. The discharging and charging reactions are
Pb+SO42PbSO4+2e       [Anodic reaction] PbO2+4H++SO42+2ePbSO4+2H2O   [Cathode reaction]

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answer is 265.

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Detailed Solution

No. of moles of H2SO4 consumed =[1.294×0.391.139×0.20]×350098=9.88
=No. of Faradays passed
 No. of Amp. Hrs =9.88×965003600=265

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