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Q.

During the disproportionation of $I_{2}$ to Iodide and Iodate ions, the ratio of Iodate and Iodide ions formed in alkaline medium is -

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a

$3 : 1$

b

$1 : 3$

c

$1 : 5$

d

$5 : 1$

answer is A.

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Detailed Solution

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The balanced chemical equation is $6 I_{2} + 12 {OH}^{-} \to 2 {IO}_{3}^{-} + 10 I^{-} + 6 H_{2} O 2 : 10$

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