During the electrolysis of cryolite, aluminum and fluorine are formed in ..... molar ratio

Cryolite : Na₃AlF₆.

The reactions taking place are 

$$\begin{gathered} \mathrm{Cathode} :\hspace{0.17em}[{\mathrm{Al}}^{3+\hspace{0.17em}}+\hspace{0.17em}3{\mathrm{e}}^{-}\to \mathrm{Al} ]\times 2 \\ \mathrm{Anode} :[\hspace{0.17em}2{\mathrm{F}}^{-} \to {\mathrm{F}}_2+\hspace{0.17em}2{\mathrm{e}}^{-}]\times 3 \end{gathered}$$

moles of Al : F₂ formed are 2 : 3.