During the electrolysis, the amount of product liberated at electrode is plotted against charge in Faraday. The correct graph is

According to the Faraday’s first law of electrolysis
$\begin{array}{l}\mathrm{W}=\frac{\mathrm{ltE}}{96500}\\ \mathrm{W}=\left(\mathrm{nF}\right){\mathrm{E}}_{\mathrm{nF}}=\text{ Number of Faraday of chargey }=\mathrm{mx}\end{array}$
When amount deposited is plotted against the number of faraday of charge, then we get
straight line passing through origin and the slope of lime (m = E) will give the equivalent
mass of the substance