During the hydrolysis of SiCl4 to form silicic acid [Si(OH)4]

H 2 O interacts with p-orbitals of “Cl”

H 2 O interacts with p-orbitals of “Cl”

H 2 O interacts with p-orbitals of “Si”

H 2 O interacts with d – orbitals of “Cl”

H 2 O interacts with p-orbitals of “Cl”

H 2 O interacts with d-orbitals of “Si”

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During the hydrolysis of SiCl₄ to form silicic acid [Si(OH)₄]

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H₂O interacts with p-orbitals of “Si”

H₂O interacts with d – orbitals of “Cl”

H₂O interacts with p-orbitals of “Cl”

H₂O interacts with d-orbitals of “Si”

answer is C.

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SiCl₄ undergoes hydrolysis by accepting lone pair of electrons from water molecule in d-orbitals of Si

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