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Q.
During the medical check-up of 35 students of a class, their weights were recorded as follows:
Weight in kg | Number of students |
Less than 38 | 0 |
Less than 40 | 3 |
Less than 42 | 5 |
Less than 44 | 9 |
Less than 46 | 14 |
Less than 48 | 28 |
Less than 50 | 32 |
Less than 52 | 35 |
Draw a less than type ogive for the given data. Hence, obtain the median weight from the graph and verify the result by using the formula.
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Detailed Solution
From the given data, to represent the table in the form of graph, choose the upper limits of the class intervals are in x-axis and frequencies on y-axis by choosing the convenient scale. Now plot the points corresponding to the ordered pairs given by (38, 0), (40, 3), (42, 5), (44, 9),(46, 14), (48, 28), (50, 32) and (52, 35) on a graph paper and join them to get a smooth curve. The curve obtained is known as less than type ogive.
Locate the point 17.5 on the y-axis and draw a line parallel to the x-axis cutting the curve at a point. From the point, draw a perpendicular line to the x-axis. The intersection point perpendicular to x-axis is the median of the given data. Now, to find the mode by making a table.
Class interval | Number of students(Frequency) | Cumulative Frequency |
Less than 38 | 0 | 0 |
Less than 40 | 3-0=3 | 3 |
Less than 42 | 5-3=2 | 5 |
Less than 44 | 9-5=4 | 9 |
Less than 46 | 14-9=5 | 14 |
Less than 48 | 28-14=14 | 28 |
Less than 50 | 32-28=4 | 32 |
Less than 52 | 35-22=3 | 35 |
The class 46 – 48 has the maximum frequency, therefore, this is modal class
Here, l = 46, h = 2, f1= 14, f0= 5 and f2 = 4
The mode formula is given as:
Now, Mode =
= 46 + 0.95 = 46.95
Thus, mode is verified.