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Q.

During the medical check-up of 35 students of a class, their weights were recorded as follows:

Weight in kgNumber of students
Less than 380
Less than 403
Less than 425
Less than 449
Less than 4614
Less than 4828
Less than 5032
Less than 5235

Draw a less than type ogive for the given data. Hence, obtain the median weight from the graph and verify the result by using the formula.

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Detailed Solution

From the given data, to represent the table in the form of graph, choose the upper limits of the class intervals are in x-axis and frequencies on y-axis by choosing the convenient scale. Now plot the points corresponding to the ordered pairs given by (38, 0), (40, 3), (42, 5), (44, 9),(46, 14), (48, 28), (50, 32) and (52, 35) on a graph paper and join them to get a smooth curve. The curve obtained is known as less than type ogive.

Ncert solutions class 10 chapter 14-10

Locate the point 17.5 on the y-axis and draw a line parallel to the x-axis cutting the curve at a point. From the point, draw a perpendicular line to the x-axis. The intersection point perpendicular to x-axis is the median of the given data. Now, to find the mode by making a table.

Class intervalNumber of students(Frequency)Cumulative Frequency
Less than 3800
Less than 403-0=33
Less than 425-3=25
Less than 449-5=49
Less than 4614-9=514
Less than 4828-14=1428
Less than 5032-28=432
Less than 5235-22=335

The class 46 – 48 has the maximum frequency, therefore, this is modal class

Here, = 46, h = 2, f1= 14, f0= 5 and f2 = 4

The mode formula is given as:

Now, Mode =

Ncert solutions class 10 chapter 14-11

= 46 + 0.95 = 46.95

Thus, mode is verified.

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