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Q.

E⁰ for the half cell ${Zn}^{2 +} / Zn is - 0.76 V$ . EMF of $the cell Zn / {Zn}^{2 +} (1 M) / / H^{+} (1 M) / H_{2}$ at 1 atm is

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a

+ 0.76V

b

–0.38V

c

–0.76V

d

+ 0.38V

answer is B.

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Detailed Solution

$E_{cell}^{o} = E_{cathode}^{o} - E_{anode}^{o} = 0 - (- 0.76) = + 0.76 V$

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E0 for the half cell Zn2+/Zn is −0.76V. EMF of the cell Zn/Zn2+(1M)//H+(1M)/H2 at 1 atm is