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Q.

E0 values for Cl2, Cl–; I2, I–; Ag+, Ag; Na+, Na; and Li+, Li are respectively + 1.36. + 0.53, + 0.79, – 2.71 and – 3.04V. Correct decreasing order of reducing strength of Cl, I–, Ag, Na and Li is 
 

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a

Cl– > I– > Ag > Na > Li 
 

b

Cl– > Ag > I– > Na > Li 
 

c

Li > Na > Ag > I– > Cl– 
 

d

Li > Na > I– > Ag > Cl– 
 

answer is D.

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Detailed Solution

  • The more negative or less positive is the electrode potential, more is the reducing strength of the species. Since the electrode potentials increases in the order
  • Li(-3.04V) < Na(-2.7V) < I-(0.53 V) < Ag(+0.79V) < Cl- (+1.36V),  therefore, the reducing strength decreases in the order 
  •  Li > Na > I- > Ag > Cl-
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