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Q.

E1,E2 and E3 are the emf values of the three galvanic cells respectively

(i)Zn|Zn2+(1M)Cu2+(0.1M)|Cu

(ii)Zn|Zn2+(1M)Cu2+(1M)|Cu

(iii)Zn|Zn2+(0.1M)Cu2+(1M)|Cu

Which one of the following is true?

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a

E2>E3>E1

b

E1>E3>E2

c

E1>E2>E3

d

E3>E2>E1

answer is B.

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Detailed Solution

Zn+Cu2+Zn2++Cu

Thus, higher the value of [Zn2+]/[Cu2+], lower is the emf of the cell. [Zn2+][Cu2+]

for (i)=10.1=10, for (ii)=11=1,for (iii)=0.11=0.1

Hence, E3>E2>E1

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