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$∆ H for {CaCO}_{3} (s) \overset{}{\to} CaO (s) + {CO}_{2} (g) is 176 kJ {mol}^{- 1}$ at 1240 K. The $∆ E$ for the change is equal to

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160 kJ

165.7 kJ

186.3 kJ

180.0 kJ

answer is B.

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Detailed Solution

$∆ H = ∆ E + ∆ nRT ∴ ∆ E = 176 - 1 \times 8.314 \times 1240 \times 10^{- 3} = 165.7 kJ$

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