Q.

E2μ0 has the dimensions (E = electric field, μ0=  permeability of free space)

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a

[ML3T2]

b

[M1L2TA2]

c

[M2L3T2A2]

d

[MLT4]

answer is B.

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Detailed Solution

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[E2μ0]=[ε0E2ε0μ0]=[energy/volume(1/speedof  light)2]

=[energy(speed)2volume]

=[ML2T2L2T2L3]=[MLT4]

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E2μ0 has the dimensions (E = electric field, μ0=  permeability of free space)