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Q.

Each mole of substance A (Molar mass = 720) requires 10 moles of water for complete hydrolysis and gives B, C and D as the hydrolysed products in a molar ratio of 2 : 3 : 2. If molecular mass of B is 40 and it contributes 40% of total mass of hydrolysed product then moles of C obtained will be :

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a

9

b

13.5

c

3

d

2

answer is B.

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Detailed Solution

$A + 10 H_{2} O ⟶ B + C + D$

$720 + 10 \times 18 = 900 2 x 3 x 2 x$

Mass of B = = 900 x 0.4 = 360 gm

Moles of B $= \frac{360}{40} = 9 = 2 x$

$\begin{array}{l} \Rightarrow x = 4.5 \\ n_{C} = 3 x = 3 \times 4.5 \\ = 13.5 \end{array}$

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Each mole of substance A (Molar mass = 720) requires 10 moles of water for complete hydrolysis and gives B, C and D as the hydrolysed products in a molar ratio of 2 : 3 : 2. If molecular mass of B is 40 and it contributes 40% of total mass of hydrolysed product then moles of C obtained will be :