Q.

Each rubidium halide crystallising in the RbCl type lattice has a unit cell length 0.30Ao greater than that for corresponding potassium salt rK+=1.33)of the same halogen. Hence, ionic radius of Rb+ is

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a

1.63A0

b

1.18A0

c

1.48A0

d

1.03A0

answer is B.

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Detailed Solution

RbCl type : 2Rb++2Cl=Edge length
KCl type : 2K++2Cl=Edge length
Edge length of RbCl > KCl by 0.3A0
2Rb++2Cl=x+0.3..(2)2K++2Cl=x(2)(1)2Rb+2K+=0.3;2Rb+2×1.33=0.3,2Rb+=2.96A0Rb+=1.48A0

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