Each side of a cube is measured to be 7.203 m. The volume of the cube to appropriate significant figures is

The number of significant figures in the measured length is 4. The volume should therefore be rounded off to 4 significant figures.

As, $V=a^3$

Given, a = 7.203 m

$\therefore V={\left(7.203\right)}^3=373.714754m^3=373.7m^3$