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Ebullioscopic constant ( $K_{b}$ ) and cryoscopic constant ( $K_{f}$ ) depend on following factor:

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moles of solute added in solvent.

freezing point and boiling point of solvent respectively.

latent heat of vaporization and fusion of solvent respectively.

molar mass of solute added.

answer is D.

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Detailed Solution

$K_{b} = \frac{{RT}_{0}^{2} M}{1000 H_{V}} K_{f} = \frac{{RT}_{0}^{2} M}{1000 H_{f}}$

So, $K_{b}$ and $K_{f}$ depends on heat of vaporization and fusion.

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