$E_{cell}^{\Theta }$ for some half cell reactions are given below. On the basis of these mark the correct answer.

$\text{ (1) }{H}^{+}\left(aq\right)+e^{-}\to \frac{1}{2}{H}_2\left(g\right);E_{cell}^{\Theta }=0.00V$

$\text{( ii) }2H_{2}O\left(l\right)\to O_2\left(g\right)+4H^{+}\left(aq\right)+4e^{-};E_{cell}^{\Theta }=1.23V$

$\text{ (iii) }2S{O}_4^{2-}\left(aq\right)\to S_2{O}_8^{2-}\left(aq\right)+2e^{-};E_{\text{cell }}^{\Theta }=1.96 \mathrm{V}$

In dilute sulphuric acid acid solution, hydrogen ion will be reduced at cathode

in dilute sulphuric acid solution, $S{O}_4^{2-}$ion will be oxidized to tetrathionate ion at anode.

In dilute sulphuric acid solution, water will be oxidized at anode

In concentrated sulphuric acid solution, water will be oxidized at anode