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Q.

Efficiency of a Carnot's engine is 100% when

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a

source is placed at 400°C

b

source is placed at 100°C

c

sink is placed at 0°C

d

sink is placed at 0 K

answer is B.

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Detailed Solution

$\begin{array}{l} η (Carnot' s cycle) = \frac{T_{2} (source) - T_{1} (sink)}{T_{2}} \\ η = 1 when T_{1} = 0 K \end{array}$

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