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Q.

Eight drops of mercury of equal radii possessing equal charges combine to form a big drop. Then the capacitance of bigger drop compared to each individual small drop is

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a

2 times

b

4 times

c

32 times

d

8 times

answer is C.

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Detailed Solution

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Volume of 8 small drops = Volume of big drop

8×43πr3=43πR3⇒R=2r

As capacity is proportional to r, hence capacity becomes 2 times.

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