Q.

Eight drops of mercury of same radius and having same charge coalesce to form a big drop. Capacitance of big drop relative to that of small drop will be

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a

4 times

b

16 times

c

2 times 

d

8 times

answer is D.

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Detailed Solution

By using relation C=n1/3c

 C=(8)1/3c=2c

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Eight drops of mercury of same radius and having same charge coalesce to form a big drop. Capacitance of big drop relative to that of small drop will be