Elastic potential energy of a spring is independent of

When a spring is stretched (or) compressed by an amount from its natural position the  energy stored in spring is called Elastic potential energy.

$\mathrm{U}=\frac{1}{2}\mathrm{k}{x}^2$

K = spring constant

x is –ve or +ve in the expression of U, even i.e., compression of elongation U remain unchanged.

Elastic P.E is Independent of elongation and compression of the spring, option (D) is correctly describing the task.