Electric charges q, q, – 2q are placed at the corners of an equilateral triangle ABC of side $l$. The magnitude of electric dipole moment of the  system is

Given data: Three charges of magnitude q, q, -2q

Concept used: Electric dipole

Detailed solution:

Here we break the -2q charge into two –q charges, and we get two dipoles 

Dipole moment of both dipoles P=q L

Both dipoles are at an angle Ɵ =60⁰ 

So, the Resultant dipole moment $P_{net}=\sqrt{P^2+P^2+2P^2\cos \theta }$

$$\begin{gathered} =\sqrt{3P^2} \\ =\sqrt{3}P \\ {P}_{net}=\sqrt{3}qL \end{gathered}$$