Electric field due to an infinite sheet of charge having surface charge density $σ$ is E. Electric field due to an infinite conducting sheet of same surface density of charge is

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$\frac{E}{2}$

answer is C.

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Detailed Solution

$\begin{aligned} E = \frac{σ}{2 ε_{0}} (Infinite sheet of charge) \\ E^{'} = \frac{σ}{ε_{0}} = 2 E (Conducting sheet) \end{aligned} Because the charge on conducting sheet will be on both sides .$

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