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Electric field inside the given capacitor with dielectric is $E$ and dielectric constant of material is $K$ . The charge density on the plates is $n \times 10^{- 5} \frac{C}{m^{2}}$ . Find the value of n. (Given $E = 6 x 10^{5} V / m, K = 6$ )

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Detailed Solution

$E = \frac{σ}{ε_{0} K}; 6 x 10^{5} = \frac{σ}{8.85 x 10^{- 12} x 6} σ = 36 x 8.85 x 10^{- 12} x 10^{5} \frac{C}{m^{2}} = 3.18 x 10^{- 5} \frac{C}{m^{2}}$

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