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Q.

Electric potential at a point in space is given as V=1x+1y+1z The electric field magnitude at point (1, 1, 1) will be 

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a

3 N/C

b

3N/C

c

23   N/C

d

33   N/C

answer is B.

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Detailed Solution

Ex=Vx=1x2     Ey=Vy=1y2

Ey=Vz=1z2

Ez=+1x2i^+1y2j^+1z2k^

at (1, 1, 1)

E=+i^+j^+k^   |E|=3N/C

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