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Electric potential at a point P, r distance away due to a point charge located at a point A is V. If twice of this charge is distributed uniformly on the surface of a hollow sphere of radius 4r with centre at point A, the potential at P now is given as

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V/4

V/2

V/8

answer is B.

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Detailed Solution

$\begin{array}{l} v = \frac{1}{4 {πε}_{0}} \frac{q}{r}; v_{surface} = v_{inside} \\ v_{centre} = \frac{1}{4 {πε}_{0}} \frac{2 q}{4 r} = \frac{v}{2} \end{array}$

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