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Q.

Electric potential at the centre of a cube having uniform volumetric charge density ‘ρ ’ and side ‘a’ is given by V0 . Then, electric potential at the tip of a square pyramid having same volumetric charge density (ρ) of base area 4a2 and height ‘a’ is:

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a

V04

b

V06

c

2V03

d

Can’t be determined

answer is C.

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Detailed Solution

V0=kρa2= potential at the centre of a cube of side ‘a’
×4a2=4V0= Potential at the centre of a cube of side ‘2a’
Six such pyramids make a cube
Potential at the tip of pyramid 4V06=2V03.

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